Calculation of flood spillway

By Ahmad Suhendra

Flood spillway was designed based on the excess water and high water in the channel carrier (head race)

Example :

Flood Spillway will be made on a channel that has a water depth of 0.691 m, with a normal discharge (Q normal) of 0.6 m^3/sec. What is the length of Flood spillway?

Spillway length (L spillway) is obtained by using the equation of calculating Weir and must be able to pass through if the flow (Q spillway) in a state of excess but not based on the flood peak.

Dicharge Coefficient (Cd)
Profile of Crest Weir	μ- factor	Cd=2.953 μ
Board, sharp edge	0.49-0.51	1.44 - 1.51
Board, round edge	0.50-0.55	1.48 - 1.62
Round overfall	0.65-0.73	1.92 - 2.16
Sharp edge,	0.64	1.89
Rounded	0.75	2.21
Roof Shaped	0.79	2,33

Standard Weir equations:
Q = Cd * L weir * (h over the top )^1.5
In this case :

• L spillway = L weir
• Q spillway = Q minor flood - Q normal = Cd * L spillway * ( h over the top)^1.5

There are some values of  Discharge Coefficient  (Cd) and in this calculation the value of Cd was taken 1.6 (Board, the round edge)

Then :

• L spillway = (Q minor flood – Q normal) / (Cd * ( h over the top)^1.5 )

To increase the water on the head race taken a number of around 20% of normal conditions and is considered as a minor flood (small flood).

• Q minor flood = 1.2 * 0.6 = 0.72 m^3/sec
• h minor flood = 1.2 * h = 1.2 x 0.691 = 0.829 m
• h over the top = 0.829 - 0.691 = 0.138 m
• Q spillway = 0.72 - 0.6 = 0.12 m3/sec
• L spillway = ( 0.12) / (1.6 * 0.138 ^1.5) = 1.46 m