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Saturday, April 25, 2015

PENSTOCK THICKNESS CALCULATION (CASE STUDY )

A hydroelectric plant is planned to be built by utilizing the waste water from the reservoir of 3.5 m3 / s, which flowed into a penstock with a diameter of 1600 mm and the thickness (e) 9 mm. As you know, the more thick penstock then the price will also be more expensive.

Try to analyze whether the specifications of the pipe can still be revised, especially for the thickness of pipe used, whether the thickness can be reduced to (e) 6 mm, thus decreasing the cost of piping.

Existing data:
  • The material used is Mild steel ( rolled welded steel pipe)
  • The diameter of the pipe /penstock (Dp) = 1.6 m (1600 mm)
  • Pipe thickness (e) = 9 mm(which will be in the analysis)
  • Penstock length (Lp) = 66 m
  • Flow of water (Qp) = 3.5m3/det
  • High gross ( H gross) = 7.3 m
  • Head Loss (H loss)= 0.3 m
  • Net Head = 7 m
  • Water velocity in thepenstock (V) = 1.74 m / s
  • Efficiency of penstock (pipe eff) = H net /  H gross * 100% = 96%
  • visc µ = 0.00114 kg / (m.det)
  • Density of  water = 1000 kg/m3
  • K (bulk modulus of water) = 2.1*10^9 N/m2
  • ts (Tensile strength pipe) = 400 * 10^6 N/m2
  • E (modulus of elasticity) = 206 * 10^9 (N/m2)
  • In this design, penstock is used having a thickness (e) = 9 mm
Working pressure (P work) of the penstock (Mild steel )
 The desired pressure of 1.5 * Gross Head (Hg)
Note: ...[3]
The addition of pressure on the penstock :
Head up to 50 m is not more 50%
Head of 50 to150 is no more than 25%
Head up to 250 m is not more 15%
Then :
Working pressure (P)   = 1.5 *  7.3  = 10.95 m
                                    = 1.5 * (7.3 / 10) = 1.095 kgf/cm2 (Bars)
                                    = 1.095 kg/cm2 *10000 cm2/m2 * 9.81 m/s2
                                    = 107,419 N/m2 (pascal)
                                    = 107,419 N/m2 * (kN/1000N) * (m2/1000000 mm2)
                                    = 0.000107419 kN/mm2

The formula for a thin tube ( if  Dp / e > 20)...[3]
Where:
e     = thickness of penstock in mm
es    = extra thickness for corrosion (1-3 mm )...[3]
Working pressure (P) = 0.000107419 kN/mm2
Dp = diameter of 1600 mm penstock
ts (Tensile strength)  = 400* 10^6 N/m2
                               = (400 * 10^6 N/m2) * (kN/1000N) * (m2/1000.000 mm2)
                               = 0.400 kN/mm2
Minimum penstock thickness (e)
e = (P * Dp) / (2 ts) + es...[2]
        Taken extra thick for corrosion es) = 3 mm
e = (0.000107419 kN/mm2x 1600 mm) / (2 x 0.400 kN/mm2) + 3 mm
e = 3.21 mm

Check the use of penstock thickness formula
Category of penstock used , Dp / e = 1600 / 3.21
                                                      = 498 > 20 (a thin tube, the formulas is ok)

The impact of pipe handling in transportation, laying, deformation, etc., it is necessary to add more rapidly the penstock thickness (in the wills of 3 mm). So thick of penstock (e) is = 3+3.21= 6.21 mm, the thickness of the penstock taken at least 6 mm (see the availability of the thickness of the penstock in the market)

Effect of Water Hammer
In the design of penstock also must take into account the effects of water and control the speed lacing.

If the H / L> 5, the surge tank is required ...[1]
In this design:
H / L   = H gross / length of pipe (L)
           = 7.3 / 66
           = 0.11 < 5
 (Not required surge tank but the effects of  water hammer still be calculated)
The thickness of the penstock (e) = 6 mm is to be used

At wills:
% Closure of the valve flow (z) = 50%
With the closing time (T close)  = 4 seconds (fast enough)
Corrosion allowed (es)             = 3 mm
Overall safety factor (SF)         = 4

Calculation:
The speed of water waves:
C wave = [(10^ (-3)* K) / (1 + (K* Dp / E* e)]^ (0.5) ...[2]
where:
  • K = bulk modulus of water 2.1x10^ 9 N/m2
  • E = modulus of elasticity of pipe material 206 * 10^9 (N/m2)
  • D = pipe diameter 1600 mm
  • e = wall thickness 6 mm
  • L = length of pipe, 66 m
By entering values:
C.wave         = [(10^(-3)* 2.1*10^9) / (1 + (2.1*10^9 x 1600 / (206 * 10^9 * 6)] ^0.5
                    = 751.5 m / s
Critical closing time of the penstock (Tc) 

The time it takes the pressure wave (pressure wave) to return again to the valve after the sudden closure, known as the critical time.

Tc = 2 L / C...[2]
     = 2 x 66 m / 751.5 m / s.
     = 0.716 seconds
T.Close  (4 sec)> Tc  (0.716 sec)... [4]

Kc   = L* z * V / ( g * Water density * H.gross *  T Close)
        = 66 m * 50 * 1.74 m / s / (9.8 * 1000 kg/m3 m/s2 * 7.3 mx 4 s)
        = 0.2
Surge pressure (H.surge )...[4]

H.surge       = H gross * [(Kc / 2) + ((Kc + (Kc^2 / 4)) ^0.5]
                  = 7.3 * [0.2 / 2 + ((0.2 + (0.22/ 4))^ 0.5
                  = 4.07 m
H.total        = H.surge + H.gross
                  = 4.07 m + 7.3 m
                  = 11.37 m (exceeds the pressure of work, a total of 11.37 m >P work 10.95 m)

For a Total Head ( H.total ) of 11.37 m , the required minimum thicknessof the penstock (e)
e     = (H.total * Dp * SF / 83700) + es
       = (11.37 m * 1600 mm * 4 / 83700) + 3 mm
       = 3, 87 mm ( penstock with a thickness of 6 mm is adequate)

Ref :
  1. AHEC/MNRE/SHP Standards/ Civil Works –  Guidelines For Layout Of Small Hydro Plants /Feb 2008. (p-77)
  2. ESHA (European Small Hydropower Association),”Layman’s Handbook on How To Develop a
    Small Hydro Site,”2nd ed, 1998 (p-144/145)
  3. Patty O.F., Tenaga Air, Erlangga, Jakarta1995 (p-62/64)
  4. STEEL PENSTOCK LOSSES & THICKNESS CALCULATION (p-1)
    http://www.energyservices.lk/pdf/techspecs/vh_w_b/pensteel.pdf

Sunday, December 25, 2011

Design of the cross flow runner

The equations in this section are taken from:
  • Arter, A., Meier, U., Harnessing Water Power on a Small Scale Hydraulics Engineering Manual(SKAT)
  • Mockmore, C. A. Prof CEng, Merryfield, F. Prof CEng, The Banki Water Turbine, 1949
  • Harvey, A, Micro Hydro Design Manual, (1993), ISBN 1-85339-103-4

Permanent Magnet Generator (PMG) Construction Manual

Hugh Piggott - Scoraig Wind Electric - February 2001
This manual describes how to build a 'permanent magnet generator' (PMG). We can also call it an 'alternator', because it generates alternating current (AC). It will not generate 'mains voltage' or 'utility power' AC. It generates low voltage, 'three phase' AC, and then changes it into 'direct current' (DC) for charging a 12 volt battery.

Sunday, December 18, 2011

Hydraulic losses in a penstock

Hydraulic losses in a penstock reduce the effective head in proportion to the length and approximately as the square of the water velocity.
Here you can download the way of calculation in xls

Friday, October 14, 2011

SLING PUMP


Written By : Lance Brown

This pump is commonly known by its commercial name of Sling Pump. It is based on a principle similar to the Archimedean screw, except it operates in a horizontal position with coiled pipe, rather than a sloped and open screw.

Wednesday, October 12, 2011

Crossflow Water Turbine Design Manual

By ; Abhiroop Chattopadhyay

The crossflow water turbine is widely considered by many to be the most efficient and apt type of turbine for applications in micro‐hydro and picohydro projects. However, it should also be noted that designing this kind of a turbine is no child’s play.Nevertheless, in this article, I will show you exactly how the designing of the turbine is to take place. With a very basic knowledge of mathematics, it is possible to design and construct an efficient working water turbine. Before, designing, just get an idea about how must hydraulic power is theoretically available at a particular site.

Tuesday, October 11, 2011

The breastshot waterwheel: design and model tests

By: G. Muller and C. Wolter

The waterwheel is one of the oldest hydraulic machines known to humankind and has been in use since antiquity. Originally built of wood, the availability of new materials, namely wrought iron, and the increasing demand for mechanical power during the industrial revolution led, in combination with the development of hydraulic engineering, to the rational design of waterwheels, resulting in much increased performance and efficiency. Three distinct types of waterwheels evolved: the overshot, the breastshot and the undershot wheel.
Overshot wheels were investigated quite thoroughly and were found to have efficiencies of more than 85% for a broad range of flowrates from 0.2 to 1.0 Q/Qmax. Only one measurement of an undershot or Zuppinger wheel is known to the authors. Researchers from the Technical University of Stuttgart in 1977 measured the efficiencies of a 42 kW Zuppinger wheel which was built in 1886 and had been in continuous operation since. The measurements showed efficiencies of 71–77%. The breastshot wheel however, which was particularly popular in Britain,was never investigated. Read more


Speed control of run-of-river variable speed hydro plants

By : J. Fraile-Ardanuy1, J. R. Wilhelmi, J. Fraile-Mora, J. I. Pérez and I. Sarasúa

The advantages of adjustable speed hydroelectric generation have been highlighted by several authors. The optimum speed for actual working conditions must be continuously implemented by means of an appropriate control system. This process gives rise to dynamic changes in operation variables. In this paper a speed control of run-of-river adjustable speed hydro plant is presented.